11413431433 has 2 divisors, whose sum is σ = 11413431434. Its totient is φ = 11413431432.

The previous prime is 11413431409. The next prime is 11413431511. The reversal of 11413431433 is 33413431411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10406448144 + 1006983289 = 102012^2 + 31733^2 .

It is an emirp because it is prime and its reverse (33413431411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11413431433 is a prime.

It is not a weakly prime, because it can be changed into another prime (11413437433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706715716 + 5706715717.

It is an arithmetic number, because the mean of its divisors is an integer number (5706715717).

Almost surely, 2^11413431433 is an apocalyptic number.

It is an amenable number.

11413431433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413431433 is an equidigital number, since it uses as much as digits as its factorization.

11413431433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 28.

Adding to 11413431433 its reverse (33413431411), we get a palindrome (44826862844).

The spelling of 11413431433 in words is "eleven billion, four hundred thirteen million, four hundred thirty-one thousand, four hundred thirty-three".