Search a number
-
+
11413432081 is a prime number
BaseRepresentation
bin10101010000100101…
…10010011100010001
31002110102101102102201
422220102302130101
5141333314311311
65124313243201
7552556400122
oct125022623421
932412342381
1011413432081
1149276484a7
122266403501
1310cb78ca0c
147a3b70049
1546c0079c1
hex2a84b2711

11413432081 has 2 divisors, whose sum is σ = 11413432082. Its totient is φ = 11413432080.

The previous prime is 11413432061. The next prime is 11413432109. The reversal of 11413432081 is 18023431411.

It is an a-pointer prime, because the next prime (11413432109) can be obtained adding 11413432081 to its sum of digits (28).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10953715600 + 459716481 = 104660^2 + 21441^2 .

It is an emirp because it is prime and its reverse (18023431411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11413432081 - 211 = 11413430033 is a prime.

It is a super-2 number, since 2×114134320812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11413432061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706716040 + 5706716041.

It is an arithmetic number, because the mean of its divisors is an integer number (5706716041).

Almost surely, 211413432081 is an apocalyptic number.

It is an amenable number.

11413432081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413432081 is an equidigital number, since it uses as much as digits as its factorization.

11413432081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 11413432081 its reverse (18023431411), we get a palindrome (29436863492).

The spelling of 11413432081 in words is "eleven billion, four hundred thirteen million, four hundred thirty-two thousand, eighty-one".