11413434433 has 4 divisors (see below), whose sum is σ = 11416341808. Its totient is φ = 11410527060.

The previous prime is 11413434427. The next prime is 11413434451. The reversal of 11413434433 is 33443431411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11413434433 - 2¹⁷ = 11413303361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11413434395 and 11413434404.

It is not an unprimeable number, because it can be changed into a prime (11413434413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1447791 + ... + 1455652.

It is an arithmetic number, because the mean of its divisors is an integer number (2854085452).

Almost surely, 2^11413434433 is an apocalyptic number.

It is an amenable number.

11413434433 is a deficient number, since it is larger than the sum of its proper divisors (2907375).

11413434433 is an equidigital number, since it uses as much as digits as its factorization.

11413434433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2907374.

The product of its digits is 20736, while the sum is 31.

Adding to 11413434433 its reverse (33443431411), we get a palindrome (44856865844).

The spelling of 11413434433 in words is "eleven billion, four hundred thirteen million, four hundred thirty-four thousand, four hundred thirty-three".