Base | Representation |
---|---|
bin | 110101001001011110… |
… | …0010011010101110101 |
3 | 101220121020001211121121 |
4 | 1222102330103111311 |
5 | 3332221403243333 |
6 | 124233240543541 |
7 | 11150233441264 |
oct | 1522274232565 |
9 | 356536054547 |
10 | 114134431093 |
11 | 44449a02411 |
12 | 1a153481bb1 |
13 | a9bbc28c37 |
14 | 574a32c5db |
15 | 2e8007432d |
hex | 1a92f13575 |
114134431093 has 2 divisors, whose sum is σ = 114134431094. Its totient is φ = 114134431092.
The previous prime is 114134431079. The next prime is 114134431121. The reversal of 114134431093 is 390134431411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112078987524 + 2055443569 = 334782^2 + 45337^2 .
It is an emirp because it is prime and its reverse (390134431411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114134431093 - 213 = 114134422901 is a prime.
It is a super-3 number, since 3×1141344310933 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114134431013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067215546 + 57067215547.
It is an arithmetic number, because the mean of its divisors is an integer number (57067215547).
Almost surely, 2114134431093 is an apocalyptic number.
It is an amenable number.
114134431093 is a deficient number, since it is larger than the sum of its proper divisors (1).
114134431093 is an equidigital number, since it uses as much as digits as its factorization.
114134431093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 114134431093 in words is "one hundred fourteen billion, one hundred thirty-four million, four hundred thirty-one thousand, ninety-three".
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