114135114031 has 2 divisors, whose sum is σ = 114135114032. Its totient is φ = 114135114030.

The previous prime is 114135114013. The next prime is 114135114053. The reversal of 114135114031 is 130411531411.

Together with previous prime (114135114013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114135114031 - 2⁵ = 114135113999 is a prime.

It is a super-2 number, since 2×114135114031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114135113987 and 114135114005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114135114091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57067557015 + 57067557016.

It is an arithmetic number, because the mean of its divisors is an integer number (57067557016).

Almost surely, 2^114135114031 is an apocalyptic number.

114135114031 is a deficient number, since it is larger than the sum of its proper divisors (1).

114135114031 is an equidigital number, since it uses as much as digits as its factorization.

114135114031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 114135114031 its reverse (130411531411), we get a palindrome (244546645442).

The spelling of 114135114031 in words is "one hundred fourteen billion, one hundred thirty-five million, one hundred fourteen thousand, thirty-one".