11414000113 has 2 divisors, whose sum is σ = 11414000114. Its totient is φ = 11414000112.

The previous prime is 11414000099. The next prime is 11414000123. The reversal of 11414000113 is 31100041411.

11414000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9610469089 + 1803531024 = 98033^2 + 42468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11414000113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11414000123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707000056 + 5707000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5707000057).

Almost surely, 2^11414000113 is an apocalyptic number.

It is an amenable number.

11414000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11414000113 is an equidigital number, since it uses as much as digits as its factorization.

11414000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11414000113 its reverse (31100041411), we get a palindrome (42514041524).

The spelling of 11414000113 in words is "eleven billion, four hundred fourteen million, one hundred thirteen", and thus it is an aban number.