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114140411103 = 338046803701
BaseRepresentation
bin110101001001101001…
…1000111010011011111
3101220121122022122122110
41222103103013103133
53332224421123403
6124234013045103
711150335325565
oct1522323072337
9356548278573
10114140411103
1144452317274
121a155486793
13a9c0240ac4
14574b047a35
152e80856103
hex1a934c74df

114140411103 has 4 divisors (see below), whose sum is σ = 152187214808. Its totient is φ = 76093607400.

The previous prime is 114140411071. The next prime is 114140411131. The reversal of 114140411103 is 301114041411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 114140411103 - 25 = 114140411071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114140411103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114140411183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19023401848 + ... + 19023401853.

It is an arithmetic number, because the mean of its divisors is an integer number (38046803702).

Almost surely, 2114140411103 is an apocalyptic number.

114140411103 is a deficient number, since it is larger than the sum of its proper divisors (38046803705).

114140411103 is an equidigital number, since it uses as much as digits as its factorization.

114140411103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38046803704.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 114140411103 its reverse (301114041411), we get a palindrome (415254452514).

The spelling of 114140411103 in words is "one hundred fourteen billion, one hundred forty million, four hundred eleven thousand, one hundred three".

Divisors: 1 3 38046803701 114140411103