1141410031 has 2 divisors, whose sum is σ = 1141410032. Its totient is φ = 1141410030.

The previous prime is 1141410013. The next prime is 1141410143. The reversal of 1141410031 is 1300141411.

Together with previous prime (1141410013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1300141411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141410031 - 2¹⁷ = 1141278959 is a prime.

It is a super-2 number, since 2×1141410031² = 2605633717734841922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1141409987 and 1141410014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141410331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570705015 + 570705016.

It is an arithmetic number, because the mean of its divisors is an integer number (570705016).

Almost surely, 2^1141410031 is an apocalyptic number.

1141410031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141410031 is an equidigital number, since it uses as much as digits as its factorization.

1141410031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1141410031 is about 33784.7603365778. The cubic root of 1141410031 is about 1045.0744453729.

Adding to 1141410031 its reverse (1300141411), we get a palindrome (2441551442).

The spelling of 1141410031 in words is "one billion, one hundred forty-one million, four hundred ten thousand, thirty-one".