11414331331 has 4 divisors (see below), whose sum is σ = 12292356832. Its totient is φ = 10536305832.

The previous prime is 11414331329. The next prime is 11414331359. The reversal of 11414331331 is 13313341411.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11414331331 - 2¹ = 11414331329 is a prime.

It is a super-2 number, since 2×11414331331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11414331296 and 11414331305.

It is not an unprimeable number, because it can be changed into a prime (11414331631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 439012731 + ... + 439012756.

It is an arithmetic number, because the mean of its divisors is an integer number (3073089208).

Almost surely, 2^11414331331 is an apocalyptic number.

11414331331 is a deficient number, since it is larger than the sum of its proper divisors (878025501).

11414331331 is an equidigital number, since it uses as much as digits as its factorization.

11414331331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 878025500.

The product of its digits is 1296, while the sum is 25.

Adding to 11414331331 its reverse (13313341411), we get a palindrome (24727672742).

The spelling of 11414331331 in words is "eleven billion, four hundred fourteen million, three hundred thirty-one thousand, three hundred thirty-one".