Base | Representation |
---|---|
bin | 10101010000101100… |
… | …10000101000111001 |
3 | 1002110111002122212212 |
4 | 22220112100220321 |
5 | 141334032422301 |
6 | 5124344544505 |
7 | 552600210413 |
oct | 125026205071 |
9 | 32414078785 |
10 | 11414342201 |
11 | 492810a269 |
12 | 2266782135 |
13 | 10cba1b052 |
14 | 7a3d299b3 |
15 | 46c1374bb |
hex | 2a8590a39 |
11414342201 has 2 divisors, whose sum is σ = 11414342202. Its totient is φ = 11414342200.
The previous prime is 11414342179. The next prime is 11414342209. The reversal of 11414342201 is 10224341411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10681015801 + 733326400 = 103349^2 + 27080^2 .
It is an emirp because it is prime and its reverse (10224341411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11414342201 - 214 = 11414325817 is a prime.
It is not a weakly prime, because it can be changed into another prime (11414342209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707171100 + 5707171101.
It is an arithmetic number, because the mean of its divisors is an integer number (5707171101).
Almost surely, 211414342201 is an apocalyptic number.
It is an amenable number.
11414342201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414342201 is an equidigital number, since it uses as much as digits as its factorization.
11414342201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11414342201 its reverse (10224341411), we get a palindrome (21638683612).
The spelling of 11414342201 in words is "eleven billion, four hundred fourteen million, three hundred forty-two thousand, two hundred one".
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