Base | Representation |
---|---|
bin | 110101001001111110… |
… | …1001001110000110111 |
3 | 101220122102001112102001 |
4 | 1222103331021300313 |
5 | 3332240231244343 |
6 | 124235045200131 |
7 | 11150531104324 |
oct | 1522375116067 |
9 | 356572045361 |
10 | 114151431223 |
11 | 44458563905 |
12 | 1a159100047 |
13 | a9c25cba9b |
14 | 574c6b5b4b |
15 | 2e817d144d |
hex | 1a93f49c37 |
114151431223 has 4 divisors (see below), whose sum is σ = 117833735488. Its totient is φ = 110469126960.
The previous prime is 114151431211. The next prime is 114151431253. The reversal of 114151431223 is 322134151411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114151431223 - 213 = 114151423031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114151431191 and 114151431200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114151431253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1841152086 + ... + 1841152147.
It is an arithmetic number, because the mean of its divisors is an integer number (29458433872).
Almost surely, 2114151431223 is an apocalyptic number.
114151431223 is a deficient number, since it is larger than the sum of its proper divisors (3682304265).
114151431223 is an equidigital number, since it uses as much as digits as its factorization.
114151431223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3682304264.
The product of its digits is 2880, while the sum is 28.
Adding to 114151431223 its reverse (322134151411), we get a palindrome (436285582634).
The spelling of 114151431223 in words is "one hundred fourteen billion, one hundred fifty-one million, four hundred thirty-one thousand, two hundred twenty-three".
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