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1141531031353 is a prime number
BaseRepresentation
bin10000100111001000100…
…011010011011100111001
311001010111021000202102011
4100213020203103130321
5122200323421000403
62232225003405521
7145321126445416
oct20471043233471
94033437022364
101141531031353
114001365645a9
121652a05238a1
13838520c633b
143d37113510d
151ea61ab1a6d
hex109c88d3739

1141531031353 has 2 divisors, whose sum is σ = 1141531031354. Its totient is φ = 1141531031352.

The previous prime is 1141531031317. The next prime is 1141531031449. The reversal of 1141531031353 is 3531301351411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1128455794944 + 13075236409 = 1062288^2 + 114347^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141531031353 - 29 = 1141531030841 is a prime.

It is not a weakly prime, because it can be changed into another prime (1141531032353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570765515676 + 570765515677.

It is an arithmetic number, because the mean of its divisors is an integer number (570765515677).

Almost surely, 21141531031353 is an apocalyptic number.

It is an amenable number.

1141531031353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141531031353 is an equidigital number, since it uses as much as digits as its factorization.

1141531031353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 1141531031353 its reverse (3531301351411), we get a palindrome (4672832382764).

The spelling of 1141531031353 in words is "one trillion, one hundred forty-one billion, five hundred thirty-one million, thirty-one thousand, three hundred fifty-three".