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1141531031317 is a prime number
BaseRepresentation
bin10000100111001000100…
…011010011011100010101
311001010111021000202100211
4100213020203103130111
5122200323421000232
62232225003405421
7145321126445335
oct20471043233425
94033437022324
101141531031317
11400136564576
121652a0523871
13838520c6311
143d3711350c5
151ea61ab1a47
hex109c88d3715

1141531031317 has 2 divisors, whose sum is σ = 1141531031318. Its totient is φ = 1141531031316.

The previous prime is 1141531031309. The next prime is 1141531031353. The reversal of 1141531031317 is 7131301351411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 974512506276 + 167018525041 = 987174^2 + 408679^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141531031317 - 23 = 1141531031309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141531031117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570765515658 + 570765515659.

It is an arithmetic number, because the mean of its divisors is an integer number (570765515659).

Almost surely, 21141531031317 is an apocalyptic number.

It is an amenable number.

1141531031317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141531031317 is an equidigital number, since it uses as much as digits as its factorization.

1141531031317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3780, while the sum is 31.

Adding to 1141531031317 its reverse (7131301351411), we get a palindrome (8272832382728).

The spelling of 1141531031317 in words is "one trillion, one hundred forty-one billion, five hundred thirty-one million, thirty-one thousand, three hundred seventeen".