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1141542112133 is a prime number
BaseRepresentation
bin10000100111001001001…
…101100100101110000101
311001010112000212201101102
4100213021031210232011
5122200334240042013
62232230041105445
7145321322566043
oct20471115445605
94033460781342
101141542112133
11400141842775
121652a4188285
13838544a5b07
143d3727bb393
151ea62a4ed58
hex109c9364b85

1141542112133 has 2 divisors, whose sum is σ = 1141542112134. Its totient is φ = 1141542112132.

The previous prime is 1141542112127. The next prime is 1141542112177. The reversal of 1141542112133 is 3312112451411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1137757155649 + 3784956484 = 1066657^2 + 61522^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141542112133 - 210 = 1141542111109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1141542112096 and 1141542112105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141542112033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570771056066 + 570771056067.

It is an arithmetic number, because the mean of its divisors is an integer number (570771056067).

Almost surely, 21141542112133 is an apocalyptic number.

It is an amenable number.

1141542112133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141542112133 is an equidigital number, since it uses as much as digits as its factorization.

1141542112133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880, while the sum is 29.

Adding to 1141542112133 its reverse (3312112451411), we get a palindrome (4453654563544).

The spelling of 1141542112133 in words is "one trillion, one hundred forty-one billion, five hundred forty-two million, one hundred twelve thousand, one hundred thirty-three".