Base | Representation |
---|---|
bin | 10101010000111010… |
… | …11100110101000111 |
3 | 1002110121122102112112 |
4 | 22220131130311013 |
5 | 141340023232033 |
6 | 5124453211235 |
7 | 552622221026 |
oct | 125035346507 |
9 | 32417572475 |
10 | 11416227143 |
11 | 4929187472 |
12 | 2267330b1b |
13 | 10cc22acb9 |
14 | 7a429a8bd |
15 | 46c3aac48 |
hex | 2a875cd47 |
11416227143 has 2 divisors, whose sum is σ = 11416227144. Its totient is φ = 11416227142.
The previous prime is 11416227091. The next prime is 11416227149. The reversal of 11416227143 is 34172261411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11416227143 - 212 = 11416223047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11416227149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5708113571 + 5708113572.
It is an arithmetic number, because the mean of its divisors is an integer number (5708113572).
Almost surely, 211416227143 is an apocalyptic number.
11416227143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11416227143 is an equidigital number, since it uses as much as digits as its factorization.
11416227143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8064, while the sum is 32.
Adding to 11416227143 its reverse (34172261411), we get a palindrome (45588488554).
The spelling of 11416227143 in words is "eleven billion, four hundred sixteen million, two hundred twenty-seven thousand, one hundred forty-three".
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