Base | Representation |
---|---|
bin | 11001111101010010000111… |
… | …011101000010000000111111 |
3 | 112222012211101010210112022121 |
4 | 121331102013131002000333 |
5 | 104430414301313343041 |
6 | 1042445310250423411 |
7 | 33021653153462632 |
oct | 3175220735020077 |
9 | 488184333715277 |
10 | 114162503262271 |
11 | 33415055976a12 |
12 | 1097955b431b67 |
13 | 4b91629b38a89 |
14 | 20296cd413c19 |
15 | d2e966ccc7d1 |
hex | 67d48774203f |
114162503262271 has 2 divisors, whose sum is σ = 114162503262272. Its totient is φ = 114162503262270.
The previous prime is 114162503262259. The next prime is 114162503262281. The reversal of 114162503262271 is 172262305261411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114162503262271 - 215 = 114162503229503 is a prime.
It is a super-4 number, since 4×1141625032622714 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3, 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114162503262281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57081251631135 + 57081251631136.
It is an arithmetic number, because the mean of its divisors is an integer number (57081251631136).
Almost surely, 2114162503262271 is an apocalyptic number.
114162503262271 is a deficient number, since it is larger than the sum of its proper divisors (1).
114162503262271 is an equidigital number, since it uses as much as digits as its factorization.
114162503262271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 43.
The spelling of 114162503262271 in words is "one hundred fourteen trillion, one hundred sixty-two billion, five hundred three million, two hundred sixty-two thousand, two hundred seventy-one".
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