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114170627157 = 338056875719
BaseRepresentation
bin110101001010100011…
…0011000010001010101
3101220200202011210021120
41222111012120101111
53332310140032112
6124241012434153
711151153214206
oct1522506302125
9356622153246
10114170627157
1144468385014
121a163618959
13a9c6590222
1457510715ad
152e83323e8c
hex1a95198455

114170627157 has 4 divisors (see below), whose sum is σ = 152227502880. Its totient is φ = 76113751436.

The previous prime is 114170627147. The next prime is 114170627161. The reversal of 114170627157 is 751726071411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114170627157 - 24 = 114170627141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114170627147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19028437857 + ... + 19028437862.

It is an arithmetic number, because the mean of its divisors is an integer number (38056875720).

Almost surely, 2114170627157 is an apocalyptic number.

It is an amenable number.

114170627157 is a deficient number, since it is larger than the sum of its proper divisors (38056875723).

114170627157 is an equidigital number, since it uses as much as digits as its factorization.

114170627157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38056875722.

The product of its (nonzero) digits is 82320, while the sum is 42.

Adding to 114170627157 its reverse (751726071411), we get a palindrome (865896698568).

The spelling of 114170627157 in words is "one hundred fourteen billion, one hundred seventy million, six hundred twenty-seven thousand, one hundred fifty-seven".

Divisors: 1 3 38056875719 114170627157