Base | Representation |
---|---|
bin | 10000100111011100011… |
… | …010000110100001010101 |
3 | 11001011100110212121200121 |
4 | 100213130122012201111 |
5 | 122202014211212123 |
6 | 2232322023511541 |
7 | 145332313150051 |
oct | 20473432064125 |
9 | 4034313777617 |
10 | 1141864163413 |
11 | 400297608656 |
12 | 165373bb85b1 |
13 | 838a61248bc |
14 | 3d3a3490c61 |
15 | 1ea80e6775d |
hex | 109dc686855 |
1141864163413 has 2 divisors, whose sum is σ = 1141864163414. Its totient is φ = 1141864163412.
The previous prime is 1141864163399. The next prime is 1141864163423. The reversal of 1141864163413 is 3143614681411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1141600360849 + 263802564 = 1068457^2 + 16242^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141864163413 - 213 = 1141864155221 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1141864163413.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141864163423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570932081706 + 570932081707.
It is an arithmetic number, because the mean of its divisors is an integer number (570932081707).
Almost surely, 21141864163413 is an apocalyptic number.
It is an amenable number.
1141864163413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141864163413 is an equidigital number, since it uses as much as digits as its factorization.
1141864163413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 43.
The spelling of 1141864163413 in words is "one trillion, one hundred forty-one billion, eight hundred sixty-four million, one hundred sixty-three thousand, four hundred thirteen".
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