Base | Representation |
---|---|
bin | 11001111101110110010001… |
… | …010100111000000111101011 |
3 | 112222100112120121010010201011 |
4 | 121331312101110320013223 |
5 | 104432033302320234121 |
6 | 1042515210325204351 |
7 | 33024526155102103 |
oct | 3175662124700753 |
9 | 488315517103634 |
10 | 114201323602411 |
11 | 3342a566a51051 |
12 | 10984b942606b7 |
13 | 4b951a5699046 |
14 | 202b533068203 |
15 | d30989e457e1 |
hex | 67dd915381eb |
114201323602411 has 2 divisors, whose sum is σ = 114201323602412. Its totient is φ = 114201323602410.
The previous prime is 114201323602403. The next prime is 114201323602433. The reversal of 114201323602411 is 114206323102411.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (114206323102411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114201323602411 - 23 = 114201323602403 is a prime.
It is not a weakly prime, because it can be changed into another prime (114201323602441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57100661801205 + 57100661801206.
It is an arithmetic number, because the mean of its divisors is an integer number (57100661801206).
Almost surely, 2114201323602411 is an apocalyptic number.
114201323602411 is a deficient number, since it is larger than the sum of its proper divisors (1).
114201323602411 is an equidigital number, since it uses as much as digits as its factorization.
114201323602411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 114201323602411 its reverse (114206323102411), we get a palindrome (228407646704822).
The spelling of 114201323602411 in words is "one hundred fourteen trillion, two hundred one billion, three hundred twenty-three million, six hundred two thousand, four hundred eleven".
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