11420134403 has 4 divisors (see below), whose sum is σ = 11685718968. Its totient is φ = 11154549840.

The previous prime is 11420134391. The next prime is 11420134447. The reversal of 11420134403 is 30443102411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30443102411 = 419 ⋅72656569.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11420134403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11420134463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132792218 + ... + 132792303.

It is an arithmetic number, because the mean of its divisors is an integer number (2921429742).

Almost surely, 2^11420134403 is an apocalyptic number.

11420134403 is a deficient number, since it is larger than the sum of its proper divisors (265584565).

11420134403 is an equidigital number, since it uses as much as digits as its factorization.

11420134403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265584564.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11420134403 its reverse (30443102411), we get a palindrome (41863236814).

The spelling of 11420134403 in words is "eleven billion, four hundred twenty million, one hundred thirty-four thousand, four hundred three".