Base | Representation |
---|---|
bin | 1010011000110010111011… |
… | …0110111101101000110001 |
3 | 1111102211212101111111112012 |
4 | 2212030232312331220301 |
5 | 2444110410133401431 |
6 | 40142441032012305 |
7 | 2256101415630041 |
oct | 246145666755061 |
9 | 44384771444465 |
10 | 11421104200241 |
11 | 370373263430a |
12 | 13455a0831095 |
13 | 64b00c12b738 |
14 | 2b6ada533721 |
15 | 14c150c3422b |
hex | a632edbda31 |
11421104200241 has 2 divisors, whose sum is σ = 11421104200242. Its totient is φ = 11421104200240.
The previous prime is 11421104200151. The next prime is 11421104200249. The reversal of 11421104200241 is 14200240112411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11420993214016 + 110986225 = 3379496^2 + 10535^2 .
It is a cyclic number.
It is not a de Polignac number, because 11421104200241 - 226 = 11421037091377 is a prime.
It is a super-2 number, since 2×114211042002412 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11421104200249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710552100120 + 5710552100121.
It is an arithmetic number, because the mean of its divisors is an integer number (5710552100121).
Almost surely, 211421104200241 is an apocalyptic number.
It is an amenable number.
11421104200241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11421104200241 is an equidigital number, since it uses as much as digits as its factorization.
11421104200241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 11421104200241 its reverse (14200240112411), we get a palindrome (25621344312652).
The spelling of 11421104200241 in words is "eleven trillion, four hundred twenty-one billion, one hundred four million, two hundred thousand, two hundred forty-one".
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