Base | Representation |
---|---|
bin | 10000100111110000101… |
… | …011101010111000101110 |
3 | 11001012020011221000101102 |
4 | 100213300223222320232 |
5 | 122203213301010014 |
6 | 2232415454243102 |
7 | 145343613320153 |
oct | 20476053527056 |
9 | 4035204830342 |
10 | 1142204313134 |
11 | 400451615125 |
12 | 165449ab6492 |
13 | 8392b73c421 |
14 | 3d3d671622a |
15 | 1eaa0c578de |
hex | 109f0aeae2e |
1142204313134 has 8 divisors (see below), whose sum is σ = 1713348229800. Its totient is φ = 571088236536.
The previous prime is 1142204313097. The next prime is 1142204313137. The reversal of 1142204313134 is 4313134022411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1142204313097 and 1142204313106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1142204313137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6857144 + ... + 7021739.
It is an arithmetic number, because the mean of its divisors is an integer number (214168528725).
Almost surely, 21142204313134 is an apocalyptic number.
1142204313134 is a deficient number, since it is larger than the sum of its proper divisors (571143916666).
1142204313134 is a wasteful number, since it uses less digits than its factorization.
1142204313134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13920034.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1142204313134 its reverse (4313134022411), we get a palindrome (5455338335545).
The spelling of 1142204313134 in words is "one trillion, one hundred forty-two billion, two hundred four million, three hundred thirteen thousand, one hundred thirty-four".
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