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1142214315403 = 7163173473629
BaseRepresentation
bin10000100111110001010…
…001110100110110001011
311001012020212202011220211
4100213301101310312023
5122203223331043103
62232420452501551
7145344064326250
oct20476121646613
94035225664824
101142214315403
11400457226a67
1216545131a8b7
1383930832025
143d3d7b9b427
151eaa1a8136d
hex109f1474d8b

1142214315403 has 4 divisors (see below), whose sum is σ = 1305387789040. Its totient is φ = 979040841768.

The previous prime is 1142214315391. The next prime is 1142214315433. The reversal of 1142214315403 is 3045134122411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1142214315403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1142214315433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81586736808 + ... + 81586736821.

It is an arithmetic number, because the mean of its divisors is an integer number (326346947260).

Almost surely, 21142214315403 is an apocalyptic number.

1142214315403 is a deficient number, since it is larger than the sum of its proper divisors (163173473637).

1142214315403 is an equidigital number, since it uses as much as digits as its factorization.

1142214315403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163173473636.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1142214315403 its reverse (3045134122411), we get a palindrome (4187348437814).

The spelling of 1142214315403 in words is "one trillion, one hundred forty-two billion, two hundred fourteen million, three hundred fifteen thousand, four hundred three".

Divisors: 1 7 163173473629 1142214315403