Base | Representation |
---|---|
bin | 10000100111110001010… |
… | …001110100110110001011 |
3 | 11001012020212202011220211 |
4 | 100213301101310312023 |
5 | 122203223331043103 |
6 | 2232420452501551 |
7 | 145344064326250 |
oct | 20476121646613 |
9 | 4035225664824 |
10 | 1142214315403 |
11 | 400457226a67 |
12 | 16545131a8b7 |
13 | 83930832025 |
14 | 3d3d7b9b427 |
15 | 1eaa1a8136d |
hex | 109f1474d8b |
1142214315403 has 4 divisors (see below), whose sum is σ = 1305387789040. Its totient is φ = 979040841768.
The previous prime is 1142214315391. The next prime is 1142214315433. The reversal of 1142214315403 is 3045134122411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1142214315403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1142214315433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81586736808 + ... + 81586736821.
It is an arithmetic number, because the mean of its divisors is an integer number (326346947260).
Almost surely, 21142214315403 is an apocalyptic number.
1142214315403 is a deficient number, since it is larger than the sum of its proper divisors (163173473637).
1142214315403 is an equidigital number, since it uses as much as digits as its factorization.
1142214315403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163173473636.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1142214315403 its reverse (3045134122411), we get a palindrome (4187348437814).
The spelling of 1142214315403 in words is "one trillion, one hundred forty-two billion, two hundred fourteen million, three hundred fifteen thousand, four hundred three".
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