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114222043501333 is a prime number
BaseRepresentation
bin11001111110001001100100…
…010101000001001100010101
3112222102112001121021001121221
4121332021210111001030111
5104432403221114020313
61042532514332410341
733026161501245505
oct3176114425011425
9488375047231557
10114222043501333
1133438329880859
1210988bb73169b1
134b9712825c471
14202c53abc7a05
15d3129deb4c8d
hex67e264541315

114222043501333 has 2 divisors, whose sum is σ = 114222043501334. Its totient is φ = 114222043501332.

The previous prime is 114222043501309. The next prime is 114222043501337. The reversal of 114222043501333 is 333105340222411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98206375667569 + 16015667833764 = 9909913^2 + 4001958^2 .

It is an emirp because it is prime and its reverse (333105340222411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114222043501333 - 237 = 114084604547861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114222043501337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111021750666 + 57111021750667.

It is an arithmetic number, because the mean of its divisors is an integer number (57111021750667).

Almost surely, 2114222043501333 is an apocalyptic number.

It is an amenable number.

114222043501333 is a deficient number, since it is larger than the sum of its proper divisors (1).

114222043501333 is an equidigital number, since it uses as much as digits as its factorization.

114222043501333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 114222043501333 its reverse (333105340222411), we get a palindrome (447327383723744).

The spelling of 114222043501333 in words is "one hundred fourteen trillion, two hundred twenty-two billion, forty-three million, five hundred one thousand, three hundred thirty-three".