Base | Representation |
---|---|
bin | 1010011000110111000011… |
… | …0010110010101100011111 |
3 | 1111102221201111000102120120 |
4 | 2212031300302302230133 |
5 | 2444120141330344403 |
6 | 40143142505450023 |
7 | 2256141010326213 |
oct | 246156062625437 |
9 | 44387644012516 |
10 | 11422210403103 |
11 | 370414aaa5955 |
12 | 134584b1a0913 |
13 | 64b157371846 |
14 | 2b6ba3408943 |
15 | 14c1b7de2e53 |
hex | a6370cb2b1f |
11422210403103 has 16 divisors (see below), whose sum is σ = 15246761644800. Its totient is φ = 7606235703744.
The previous prime is 11422210403089. The next prime is 11422210403119. The reversal of 11422210403103 is 30130401222411.
It is not a de Polignac number, because 11422210403103 - 29 = 11422210402591 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11422210403803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17048200 + ... + 17705522.
It is an arithmetic number, because the mean of its divisors is an integer number (952922602800).
Almost surely, 211422210403103 is an apocalyptic number.
11422210403103 is a deficient number, since it is larger than the sum of its proper divisors (3824551241697).
11422210403103 is a wasteful number, since it uses less digits than its factorization.
11422210403103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 663838.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 11422210403103 its reverse (30130401222411), we get a palindrome (41552611625514).
The spelling of 11422210403103 in words is "eleven trillion, four hundred twenty-two billion, two hundred ten million, four hundred three thousand, one hundred three".
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