1142234121433 has 2 divisors, whose sum is σ = 1142234121434. Its totient is φ = 1142234121432.

The previous prime is 1142234121397. The next prime is 1142234121481. The reversal of 1142234121433 is 3341214322411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1141923057664 + 311063769 = 1068608^2 + 17637^2 .

It is a cyclic number.

It is not a de Polignac number, because 1142234121433 - 2²¹ = 1142232024281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1142234121395 and 1142234121404.

It is not a weakly prime, because it can be changed into another prime (1142234221433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571117060716 + 571117060717.

It is an arithmetic number, because the mean of its divisors is an integer number (571117060717).

Almost surely, 2^{1142234121433} is an apocalyptic number.

It is an amenable number.

1142234121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142234121433 is an equidigital number, since it uses as much as digits as its factorization.

1142234121433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13824, while the sum is 31.

Adding to 1142234121433 its reverse (3341214322411), we get a palindrome (4483448443844).

The spelling of 1142234121433 in words is "one trillion, one hundred forty-two billion, two hundred thirty-four million, one hundred twenty-one thousand, four hundred thirty-three".