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114225123400142 = 257112561700071
BaseRepresentation
bin11001111110001100011011…
…111001111001100111001110
3112222102211000020122010112012
4121332030123321321213032
5104432431023042301032
61042534144113341222
733026331020043356
oct3176143371714716
9488384006563465
10114225123400142
113343966a353377
1210989716867812
134b974c9369cb1
14202c74dc6bb66
15d313ce58c6b2
hex67e31be799ce

114225123400142 has 4 divisors (see below), whose sum is σ = 171337685100216. Its totient is φ = 57112561700070.

The previous prime is 114225123400123. The next prime is 114225123400153. The reversal of 114225123400142 is 241004321522411.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 114225123400099 and 114225123400108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28556280850034 + ... + 28556280850037.

It is an arithmetic number, because the mean of its divisors is an integer number (42834421275054).

Almost surely, 2114225123400142 is an apocalyptic number.

114225123400142 is a deficient number, since it is larger than the sum of its proper divisors (57112561700074).

114225123400142 is an equidigital number, since it uses as much as digits as its factorization.

114225123400142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57112561700073.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 114225123400142 its reverse (241004321522411), we get a palindrome (355229444922553).

The spelling of 114225123400142 in words is "one hundred fourteen trillion, two hundred twenty-five billion, one hundred twenty-three million, four hundred thousand, one hundred forty-two".

Divisors: 1 2 57112561700071 114225123400142