114231424113031 has 2 divisors, whose sum is σ = 114231424113032. Its totient is φ = 114231424113030.

The previous prime is 114231424113013. The next prime is 114231424113041. The reversal of 114231424113031 is 130311424132411.

Together with previous prime (114231424113013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114231424113031 - 2⁷ = 114231424112903 is a prime.

It is a super-2 number, since 2×114231424113031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114231424112984 and 114231424113002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114231424113011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57115712056515 + 57115712056516.

It is an arithmetic number, because the mean of its divisors is an integer number (57115712056516).

Almost surely, 2^{114231424113031} is an apocalyptic number.

114231424113031 is a deficient number, since it is larger than the sum of its proper divisors (1).

114231424113031 is an equidigital number, since it uses as much as digits as its factorization.

114231424113031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 114231424113031 its reverse (130311424132411), we get a palindrome (244542848245442).

The spelling of 114231424113031 in words is "one hundred fourteen trillion, two hundred thirty-one billion, four hundred twenty-four million, one hundred thirteen thousand, thirty-one".