Base | Representation |
---|---|
bin | 10101010001110001… |
… | …00000100111100011 |
3 | 1002111002222210212012 |
4 | 22220320200213203 |
5 | 141343332224142 |
6 | 5125305223135 |
7 | 553036423352 |
oct | 125070404743 |
9 | 32432883765 |
10 | 11423320547 |
11 | 4932191891 |
12 | 2269791aab |
13 | 1100842892 |
14 | 7a51c5999 |
15 | 46cd0c882 |
hex | 2a8e209e3 |
11423320547 has 2 divisors, whose sum is σ = 11423320548. Its totient is φ = 11423320546.
The previous prime is 11423320537. The next prime is 11423320549. The reversal of 11423320547 is 74502332411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11423320547 - 214 = 11423304163 is a prime.
Together with 11423320549, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11423320549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711660273 + 5711660274.
It is an arithmetic number, because the mean of its divisors is an integer number (5711660274).
Almost surely, 211423320547 is an apocalyptic number.
11423320547 is a deficient number, since it is larger than the sum of its proper divisors (1).
11423320547 is an equidigital number, since it uses as much as digits as its factorization.
11423320547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 11423320547 its reverse (74502332411), we get a palindrome (85925652958).
The spelling of 11423320547 in words is "eleven billion, four hundred twenty-three million, three hundred twenty thousand, five hundred forty-seven".
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