Base | Representation |
---|---|
bin | 110101001100101000… |
… | …0010010000111101011 |
3 | 101220212121100011201022 |
4 | 1222121100102013223 |
5 | 3332431011113032 |
6 | 124251542443055 |
7 | 11152660542125 |
oct | 1523120220753 |
9 | 356777304638 |
10 | 114240332267 |
11 | 444a3764546 |
12 | 1a182a3348b |
13 | aa07b57759 |
14 | 575a418215 |
15 | 2e894e2512 |
hex | 1a994121eb |
114240332267 has 2 divisors, whose sum is σ = 114240332268. Its totient is φ = 114240332266.
The previous prime is 114240332263. The next prime is 114240332309. The reversal of 114240332267 is 762233042411.
It is a weak prime.
It is an emirp because it is prime and its reverse (762233042411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114240332267 - 22 = 114240332263 is a prime.
It is a super-2 number, since 2×1142403322672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114240332263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120166133 + 57120166134.
It is an arithmetic number, because the mean of its divisors is an integer number (57120166134).
Almost surely, 2114240332267 is an apocalyptic number.
114240332267 is a deficient number, since it is larger than the sum of its proper divisors (1).
114240332267 is an equidigital number, since it uses as much as digits as its factorization.
114240332267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 114240332267 its reverse (762233042411), we get a palindrome (876473374678).
The spelling of 114240332267 in words is "one hundred fourteen billion, two hundred forty million, three hundred thirty-two thousand, two hundred sixty-seven".
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