Base | Representation |
---|---|
bin | 10000100111111101000… |
… | …000101000010110110111 |
3 | 11001012202121002121210222 |
4 | 100213331000220112313 |
5 | 122204124222300031 |
6 | 2232452203204555 |
7 | 145352004264452 |
oct | 20477500502667 |
9 | 4035677077728 |
10 | 1142411134391 |
11 | 400548336a8a |
12 | 1654a721675b |
13 | 83962544477 |
14 | 3d415d92499 |
15 | 1eab3eace7b |
hex | 109fd0285b7 |
1142411134391 has 2 divisors, whose sum is σ = 1142411134392. Its totient is φ = 1142411134390.
The previous prime is 1142411134349. The next prime is 1142411134427. The reversal of 1142411134391 is 1934311142411.
It is a strong prime.
It is an emirp because it is prime and its reverse (1934311142411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1142411134391 - 230 = 1141337392567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1142411139391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571205567195 + 571205567196.
It is an arithmetic number, because the mean of its divisors is an integer number (571205567196).
Almost surely, 21142411134391 is an apocalyptic number.
1142411134391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142411134391 is an equidigital number, since it uses as much as digits as its factorization.
1142411134391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 35.
The spelling of 1142411134391 in words is "one trillion, one hundred forty-two billion, four hundred eleven million, one hundred thirty-four thousand, three hundred ninety-one".
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