Base | Representation |
---|---|
bin | 11001111110011011010101… |
… | …101100110011100001111001 |
3 | 112222111100022110021112201012 |
4 | 121332123111230303201321 |
5 | 104433211311102301132 |
6 | 1042545352024403305 |
7 | 33030435405053645 |
oct | 3176332554634171 |
9 | 488440273245635 |
10 | 114241125431417 |
11 | 33445431056306 |
12 | 10990841916535 |
13 | 4b98b7968495a |
14 | 202d42b1abc25 |
15 | d31a193350b2 |
hex | 67e6d5b33879 |
114241125431417 has 2 divisors, whose sum is σ = 114241125431418. Its totient is φ = 114241125431416.
The previous prime is 114241125431413. The next prime is 114241125431527. The reversal of 114241125431417 is 714134521142411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111038990550016 + 3202134881401 = 10537504^2 + 1789451^2 .
It is a cyclic number.
It is not a de Polignac number, because 114241125431417 - 22 = 114241125431413 is a prime.
It is not a weakly prime, because it can be changed into another prime (114241125431413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120562715708 + 57120562715709.
It is an arithmetic number, because the mean of its divisors is an integer number (57120562715709).
Almost surely, 2114241125431417 is an apocalyptic number.
It is an amenable number.
114241125431417 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241125431417 is an equidigital number, since it uses as much as digits as its factorization.
114241125431417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 107520, while the sum is 41.
Adding to 114241125431417 its reverse (714134521142411), we get a palindrome (828375646573828).
The spelling of 114241125431417 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred twenty-five million, four hundred thirty-one thousand, four hundred seventeen".
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