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114241125431527 is a prime number
BaseRepresentation
bin11001111110011011010101…
…101100110011100011100111
3112222111100022110021112212021
4121332123111230303203213
5104433211311102302102
61042545352024404011
733030435405054163
oct3176332554634347
9488440273245767
10114241125431527
11334454310563a6
1210990841916607
134b98b79684a13
14202d42b1abca3
15d31a19335137
hex67e6d5b338e7

114241125431527 has 2 divisors, whose sum is σ = 114241125431528. Its totient is φ = 114241125431526.

The previous prime is 114241125431417. The next prime is 114241125431557. The reversal of 114241125431527 is 725134521142411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114241125431527 - 211 = 114241125429479 is a prime.

It is a super-3 number, since 3×1142411254315273 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114241125431557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120562715763 + 57120562715764.

It is an arithmetic number, because the mean of its divisors is an integer number (57120562715764).

Almost surely, 2114241125431527 is an apocalyptic number.

114241125431527 is a deficient number, since it is larger than the sum of its proper divisors (1).

114241125431527 is an equidigital number, since it uses as much as digits as its factorization.

114241125431527 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 268800, while the sum is 43.

Adding to 114241125431527 its reverse (725134521142411), we get a palindrome (839375646573938).

The spelling of 114241125431527 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred twenty-five million, four hundred thirty-one thousand, five hundred twenty-seven".