114241320331 has 2 divisors, whose sum is σ = 114241320332. Its totient is φ = 114241320330.

The previous prime is 114241320301. The next prime is 114241320343. The reversal of 114241320331 is 133023142411.

It is a strong prime.

It is an emirp because it is prime and its reverse (133023142411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114241320331 - 2⁵ = 114241320299 is a prime.

It is a super-2 number, since 2×114241320331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114241320296 and 114241320305.

It is not a weakly prime, because it can be changed into another prime (114241320301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120660165 + 57120660166.

It is an arithmetic number, because the mean of its divisors is an integer number (57120660166).

Almost surely, 2^114241320331 is an apocalyptic number.

114241320331 is a deficient number, since it is larger than the sum of its proper divisors (1).

114241320331 is an equidigital number, since it uses as much as digits as its factorization.

114241320331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 114241320331 its reverse (133023142411), we get a palindrome (247264462742).

The spelling of 114241320331 in words is "one hundred fourteen billion, two hundred forty-one million, three hundred twenty thousand, three hundred thirty-one".