Base | Representation |
---|---|
bin | 10101010001110111… |
… | …00111000001011101 |
3 | 1002111011112002121221 |
4 | 22220323213001131 |
5 | 141344034230323 |
6 | 5125334453341 |
7 | 553046346553 |
oct | 125073470135 |
9 | 32434462557 |
10 | 11424133213 |
11 | 4932697409 |
12 | 2269b04251 |
13 | 1100a6874c |
14 | 7a5357bd3 |
15 | 46ce1d55d |
hex | 2a8ee705d |
11424133213 has 2 divisors, whose sum is σ = 11424133214. Its totient is φ = 11424133212.
The previous prime is 11424133181. The next prime is 11424133223. The reversal of 11424133213 is 31233142411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9393098724 + 2031034489 = 96918^2 + 45067^2 .
It is an emirp because it is prime and its reverse (31233142411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11424133213 - 25 = 11424133181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11424133223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712066606 + 5712066607.
It is an arithmetic number, because the mean of its divisors is an integer number (5712066607).
Almost surely, 211424133213 is an apocalyptic number.
It is an amenable number.
11424133213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424133213 is an equidigital number, since it uses as much as digits as its factorization.
11424133213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 25.
Adding to 11424133213 its reverse (31233142411), we get a palindrome (42657275624).
The spelling of 11424133213 in words is "eleven billion, four hundred twenty-four million, one hundred thirty-three thousand, two hundred thirteen".
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