Base | Representation |
---|---|
bin | 11001111110011100010001… |
… | …110011110001000010110111 |
3 | 112222111102220201212111201201 |
4 | 121332130101303301002313 |
5 | 104433220342233423312 |
6 | 1042550040051233331 |
7 | 33030502401602062 |
oct | 3176342163610267 |
9 | 488442821774651 |
10 | 114242133889207 |
11 | 334458a93265a5 |
12 | 10990a835a8847 |
13 | 4b98caa59373c |
14 | 202d4c50bb8d9 |
15 | d31a77b37557 |
hex | 67e711cf10b7 |
114242133889207 has 2 divisors, whose sum is σ = 114242133889208. Its totient is φ = 114242133889206.
The previous prime is 114242133889199. The next prime is 114242133889241. The reversal of 114242133889207 is 702988331242411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114242133889207 - 23 = 114242133889199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114242133889607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121066944603 + 57121066944604.
It is an arithmetic number, because the mean of its divisors is an integer number (57121066944604).
Almost surely, 2114242133889207 is an apocalyptic number.
114242133889207 is a deficient number, since it is larger than the sum of its proper divisors (1).
114242133889207 is an equidigital number, since it uses as much as digits as its factorization.
114242133889207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4644864, while the sum is 55.
The spelling of 114242133889207 in words is "one hundred fourteen trillion, two hundred forty-two billion, one hundred thirty-three million, eight hundred eighty-nine thousand, two hundred seven".
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