114243021443121 has 4 divisors (see below), whose sum is σ = 152324028590832. Its totient is φ = 76162014295412.

The previous prime is 114243021443101. The next prime is 114243021443123. The reversal of 114243021443121 is 121344120342411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114243021443121 is a prime.

It is a super-2 number, since 2×114243021443121² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (114243021443123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19040503573851 + ... + 19040503573856.

It is an arithmetic number, because the mean of its divisors is an integer number (38081007147708).

Almost surely, 2^{114243021443121} is an apocalyptic number.

It is an amenable number.

114243021443121 is a deficient number, since it is larger than the sum of its proper divisors (38081007147711).

114243021443121 is an equidigital number, since it uses as much as digits as its factorization.

114243021443121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38081007147710.

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 114243021443121 its reverse (121344120342411), we get a palindrome (235587141785532).

The spelling of 114243021443121 in words is "one hundred fourteen trillion, two hundred forty-three billion, twenty-one million, four hundred forty-three thousand, one hundred twenty-one".