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114243433 is a prime number
BaseRepresentation
bin1101100111100…
…11011101101001
321221222011112021
412303303131221
5213221242213
615200344441
72555024143
oct663633551
9257864467
10114243433
115953a867
1232315121
131a88c985
141125bc93
15a069d8d
hex6cf3769

114243433 has 2 divisors, whose sum is σ = 114243434. Its totient is φ = 114243432.

The previous prime is 114243427. The next prime is 114243449. The reversal of 114243433 is 334342411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76947984 + 37295449 = 8772^2 + 6107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114243433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114243398 and 114243407.

It is not a weakly prime, because it can be changed into another prime (114243413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121716 + 57121717.

It is an arithmetic number, because the mean of its divisors is an integer number (57121717).

Almost surely, 2114243433 is an apocalyptic number.

It is an amenable number.

114243433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114243433 is an equidigital number, since it uses as much as digits as its factorization.

114243433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3456, while the sum is 25.

The square root of 114243433 is about 10688.4719674984. The cubic root of 114243433 is about 485.2256476487.

Adding to 114243433 its reverse (334342411), we get a palindrome (448585844).

The spelling of 114243433 in words is "one hundred fourteen million, two hundred forty-three thousand, four hundred thirty-three".