Base | Representation |
---|---|
bin | 110101001100101111… |
… | …1110100100000110111 |
3 | 101220212220000002212111 |
4 | 1222121133310200313 |
5 | 3332433031432203 |
6 | 124252210031451 |
7 | 11153040264640 |
oct | 1523137644067 |
9 | 356786002774 |
10 | 114244405303 |
11 | 444a5a96696 |
12 | 1a184278587 |
13 | aa08952632 |
14 | 575ab986c7 |
15 | 2e89a4926d |
hex | 1a997f4837 |
114244405303 has 8 divisors (see below), whose sum is σ = 137436878720. Its totient is φ = 92769892920.
The previous prime is 114244405291. The next prime is 114244405309. The reversal of 114244405303 is 303504442411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114244405303 is a prime.
It is a super-2 number, since 2×1142444053032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114244405309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 429490113 + ... + 429490378.
It is an arithmetic number, because the mean of its divisors is an integer number (17179609840).
Almost surely, 2114244405303 is an apocalyptic number.
114244405303 is a deficient number, since it is larger than the sum of its proper divisors (23192473417).
114244405303 is an equidigital number, since it uses as much as digits as its factorization.
114244405303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 858980517.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 114244405303 its reverse (303504442411), we get a palindrome (417748847714).
The spelling of 114244405303 in words is "one hundred fourteen billion, two hundred forty-four million, four hundred five thousand, three hundred three".
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