Base | Representation |
---|---|
bin | 11001111110011110111111… |
… | …000111011110001000101111 |
3 | 112222111201102101002002202002 |
4 | 121332132333013132020233 |
5 | 104433242321111404012 |
6 | 1042551240355522515 |
7 | 33030634426154306 |
oct | 3176367707361057 |
9 | 488451371062662 |
10 | 114245041513007 |
11 | 33447060632379 |
12 | 109915552b943b |
13 | 4b99351aa35b2 |
14 | 202d6bd31943d |
15 | d31b980307c2 |
hex | 67e7bf1de22f |
114245041513007 has 2 divisors, whose sum is σ = 114245041513008. Its totient is φ = 114245041513006.
The previous prime is 114245041512949. The next prime is 114245041513037. The reversal of 114245041513007 is 700315140542411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114245041513007 - 228 = 114244773077551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114245041513037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57122520756503 + 57122520756504.
It is an arithmetic number, because the mean of its divisors is an integer number (57122520756504).
Almost surely, 2114245041513007 is an apocalyptic number.
114245041513007 is a deficient number, since it is larger than the sum of its proper divisors (1).
114245041513007 is an equidigital number, since it uses as much as digits as its factorization.
114245041513007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 38.
The spelling of 114245041513007 in words is "one hundred fourteen trillion, two hundred forty-five billion, forty-one million, five hundred thirteen thousand, seven".
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