1142491426943 has 2 divisors, whose sum is σ = 1142491426944. Its totient is φ = 1142491426942.

The previous prime is 1142491426891. The next prime is 1142491427047. The reversal of 1142491426943 is 3496241942411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1142491426943 - 2³⁰ = 1141417685119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1142491426891 and 1142491426900.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1142491426343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571245713471 + 571245713472.

It is an arithmetic number, because the mean of its divisors is an integer number (571245713472).

Almost surely, 2^{1142491426943} is an apocalyptic number.

1142491426943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142491426943 is an equidigital number, since it uses as much as digits as its factorization.

1142491426943 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1492992, while the sum is 50.

The spelling of 1142491426943 in words is "one trillion, one hundred forty-two billion, four hundred ninety-one million, four hundred twenty-six thousand, nine hundred forty-three".