Base | Representation |
---|---|
bin | 1010011001000010010110… |
… | …1100011101111111000011 |
3 | 1111110020112222221100010121 |
4 | 2212100211230131333003 |
5 | 2444142400311442012 |
6 | 40144404004441111 |
7 | 2256306142501321 |
oct | 246204554357703 |
9 | 44406488840117 |
10 | 11425245421507 |
11 | 3705468204125 |
12 | 13463576a9197 |
13 | 64b51c097318 |
14 | 2b6db0528d11 |
15 | 14c2e45a2a07 |
hex | a6425b1dfc3 |
11425245421507 has 2 divisors, whose sum is σ = 11425245421508. Its totient is φ = 11425245421506.
The previous prime is 11425245421483. The next prime is 11425245421589. The reversal of 11425245421507 is 70512454252411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11425245421507 is a prime.
It is not a weakly prime, because it can be changed into another prime (11425645421507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712622710753 + 5712622710754.
It is an arithmetic number, because the mean of its divisors is an integer number (5712622710754).
Almost surely, 211425245421507 is an apocalyptic number.
11425245421507 is a deficient number, since it is larger than the sum of its proper divisors (1).
11425245421507 is an equidigital number, since it uses as much as digits as its factorization.
11425245421507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448000, while the sum is 43.
Adding to 11425245421507 its reverse (70512454252411), we get a palindrome (81937699673918).
The spelling of 11425245421507 in words is "eleven trillion, four hundred twenty-five billion, two hundred forty-five million, four hundred twenty-one thousand, five hundred seven".
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