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11425245421507 is a prime number
BaseRepresentation
bin1010011001000010010110…
…1100011101111111000011
31111110020112222221100010121
42212100211230131333003
52444142400311442012
640144404004441111
72256306142501321
oct246204554357703
944406488840117
1011425245421507
113705468204125
1213463576a9197
1364b51c097318
142b6db0528d11
1514c2e45a2a07
hexa6425b1dfc3

11425245421507 has 2 divisors, whose sum is σ = 11425245421508. Its totient is φ = 11425245421506.

The previous prime is 11425245421483. The next prime is 11425245421589. The reversal of 11425245421507 is 70512454252411.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11425245421507 is a prime.

It is not a weakly prime, because it can be changed into another prime (11425645421507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712622710753 + 5712622710754.

It is an arithmetic number, because the mean of its divisors is an integer number (5712622710754).

Almost surely, 211425245421507 is an apocalyptic number.

11425245421507 is a deficient number, since it is larger than the sum of its proper divisors (1).

11425245421507 is an equidigital number, since it uses as much as digits as its factorization.

11425245421507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448000, while the sum is 43.

Adding to 11425245421507 its reverse (70512454252411), we get a palindrome (81937699673918).

The spelling of 11425245421507 in words is "eleven trillion, four hundred twenty-five billion, two hundred forty-five million, four hundred twenty-one thousand, five hundred seven".