Base | Representation |
---|---|
bin | 11001111110100101111100… |
… | …011101011100001000010111 |
3 | 112222112102201002020201122102 |
4 | 121332211330131130020113 |
5 | 104433403121330224304 |
6 | 1042554514022352315 |
7 | 33031320532660226 |
oct | 3176457435341027 |
9 | 488472632221572 |
10 | 114252513133079 |
11 | 3344a24511a0a2 |
12 | 10992a9b58b69b |
13 | 4b99c72a05b69 |
14 | 202dbcb760cbd |
15 | d31e83e58d1e |
hex | 67e97c75c217 |
114252513133079 has 2 divisors, whose sum is σ = 114252513133080. Its totient is φ = 114252513133078.
The previous prime is 114252513133049. The next prime is 114252513133093. The reversal of 114252513133079 is 970331315252411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114252513133079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114252513133009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57126256566539 + 57126256566540.
It is an arithmetic number, because the mean of its divisors is an integer number (57126256566540).
Almost surely, 2114252513133079 is an apocalyptic number.
114252513133079 is a deficient number, since it is larger than the sum of its proper divisors (1).
114252513133079 is an equidigital number, since it uses as much as digits as its factorization.
114252513133079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 680400, while the sum is 47.
The spelling of 114252513133079 in words is "one hundred fourteen trillion, two hundred fifty-two billion, five hundred thirteen million, one hundred thirty-three thousand, seventy-nine".
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