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114254031120041 is a prime number
BaseRepresentation
bin11001111110100111010110…
…111100000110011010101001
3112222112120121212121110021202
4121332213112330012122221
5104433414223431320131
61042555324410213545
733031403254441211
oct3176472674063251
9488476555543252
10114254031120041
113344a953a7517a
1210993243a242b5
134b9a1553551b7
14202dcd31c7241
15d32022357bcb
hex67e9d6f066a9

114254031120041 has 2 divisors, whose sum is σ = 114254031120042. Its totient is φ = 114254031120040.

The previous prime is 114254031120011. The next prime is 114254031120161. The reversal of 114254031120041 is 140021130452411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101872605494416 + 12381425625625 = 10093196^2 + 3518725^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114254031120041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114254031119986 and 114254031120013.

It is not a weakly prime, because it can be changed into another prime (114254031120011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127015560020 + 57127015560021.

It is an arithmetic number, because the mean of its divisors is an integer number (57127015560021).

Almost surely, 2114254031120041 is an apocalyptic number.

It is an amenable number.

114254031120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

114254031120041 is an equidigital number, since it uses as much as digits as its factorization.

114254031120041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 114254031120041 its reverse (140021130452411), we get a palindrome (254275161572452).

The spelling of 114254031120041 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty-one million, one hundred twenty thousand, forty-one".