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114254031120161 is a prime number
BaseRepresentation
bin11001111110100111010110…
…111100000110011100100001
3112222112120121212121110110012
4121332213112330012130201
5104433414223431321121
61042555324410214305
733031403254441442
oct3176472674063441
9488476555543405
10114254031120161
113344a953a75279
1210993243a24395
134b9a15535527a
14202dcd31c72c9
15d32022357c5b
hex67e9d6f06721

114254031120161 has 2 divisors, whose sum is σ = 114254031120162. Its totient is φ = 114254031120160.

The previous prime is 114254031120041. The next prime is 114254031120167. The reversal of 114254031120161 is 161021130452411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74109388559761 + 40144642560400 = 8608681^2 + 6335980^2 .

It is a cyclic number.

It is not a de Polignac number, because 114254031120161 - 242 = 109855984609057 is a prime.

It is not a weakly prime, because it can be changed into another prime (114254031120167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127015560080 + 57127015560081.

It is an arithmetic number, because the mean of its divisors is an integer number (57127015560081).

Almost surely, 2114254031120161 is an apocalyptic number.

It is an amenable number.

114254031120161 is a deficient number, since it is larger than the sum of its proper divisors (1).

114254031120161 is an equidigital number, since it uses as much as digits as its factorization.

114254031120161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 32.

Adding to 114254031120161 its reverse (161021130452411), we get a palindrome (275275161572572).

The spelling of 114254031120161 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty-one million, one hundred twenty thousand, one hundred sixty-one".