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114254031120407 is a prime number
BaseRepresentation
bin11001111110100111010110…
…111100000110100000010111
3112222112120121212121110210022
4121332213112330012200113
5104433414223431323112
61042555324410215355
733031403254442243
oct3176472674064027
9488476555543708
10114254031120407
113344a953a75482
1210993243a2455b
134b9a155355409
14202dcd31c7423
15d32022357d72
hex67e9d6f06817

114254031120407 has 2 divisors, whose sum is σ = 114254031120408. Its totient is φ = 114254031120406.

The previous prime is 114254031120287. The next prime is 114254031120521. The reversal of 114254031120407 is 704021130452411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114254031120407 - 210 = 114254031119383 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114254031140407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127015560203 + 57127015560204.

It is an arithmetic number, because the mean of its divisors is an integer number (57127015560204).

Almost surely, 2114254031120407 is an apocalyptic number.

114254031120407 is a deficient number, since it is larger than the sum of its proper divisors (1).

114254031120407 is an equidigital number, since it uses as much as digits as its factorization.

114254031120407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 114254031120407 its reverse (704021130452411), we get a palindrome (818275161572818).

The spelling of 114254031120407 in words is "one hundred fourteen trillion, two hundred fifty-four billion, thirty-one million, one hundred twenty thousand, four hundred seven".