114255011121135 has 16 divisors (see below), whose sum is σ = 182808256742496. Its totient is φ = 60935926281728.

The previous prime is 114255011121131. The next prime is 114255011121149. The reversal of 114255011121135 is 531121110552411.

It is a cyclic number.

It is not a de Polignac number, because 114255011121135 - 2² = 114255011121131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114255011121096 and 114255011121105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114255011121131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7965907 + ... + 17087003.

It is an arithmetic number, because the mean of its divisors is an integer number (11425516046406).

Almost surely, 2^{114255011121135} is an apocalyptic number.

114255011121135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

114255011121135 is a deficient number, since it is larger than the sum of its proper divisors (68553245621361).

114255011121135 is an equidigital number, since it uses as much as digits as its factorization.

114255011121135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9956202.

The product of its (nonzero) digits is 6000, while the sum is 33.

Adding to 114255011121135 its reverse (531121110552411), we get a palindrome (645376121673546).

The spelling of 114255011121135 in words is "one hundred fourteen trillion, two hundred fifty-five billion, eleven million, one hundred twenty-one thousand, one hundred thirty-five".