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11425554013 is a prime number
BaseRepresentation
bin10101010010000010…
…00001111001011101
31002111021012021121011
422221001001321131
5141344420212023
65125425135221
7553064415046
oct125101017135
932437167534
1011425554013
114933477925
12226a48a511
131101145363
147a56078cd
1546d0ee50d
hex2a9041e5d

11425554013 has 2 divisors, whose sum is σ = 11425554014. Its totient is φ = 11425554012.

The previous prime is 11425553983. The next prime is 11425554017. The reversal of 11425554013 is 31045552411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11422906884 + 2647129 = 106878^2 + 1627^2 .

It is a cyclic number.

It is not a de Polignac number, because 11425554013 - 25 = 11425553981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11425554017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712777006 + 5712777007.

It is an arithmetic number, because the mean of its divisors is an integer number (5712777007).

Almost surely, 211425554013 is an apocalyptic number.

It is an amenable number.

11425554013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11425554013 is an equidigital number, since it uses as much as digits as its factorization.

11425554013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 11425554013 in words is "eleven billion, four hundred twenty-five million, five hundred fifty-four thousand, thirteen".