Base | Representation |
---|---|
bin | 11001111110101000110001… |
… | …011110001101001011100011 |
3 | 112222112201112201200001201111 |
4 | 121332220301132031023203 |
5 | 104433430331300310313 |
6 | 1043000135225244151 |
7 | 33031456020003106 |
oct | 3176506136151343 |
9 | 488481481601644 |
10 | 114255550010083 |
11 | 334505633877a9 |
12 | 109935a8633657 |
13 | 4b9a337c2c5c1 |
14 | 202ddd8c0673d |
15 | d320b088443d |
hex | 67ea3178d2e3 |
114255550010083 has 2 divisors, whose sum is σ = 114255550010084. Its totient is φ = 114255550010082.
The previous prime is 114255550009963. The next prime is 114255550010101. The reversal of 114255550010083 is 380010055552411.
It is a strong prime.
It is an emirp because it is prime and its reverse (380010055552411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114255550010083 - 217 = 114255549879011 is a prime.
It is not a weakly prime, because it can be changed into another prime (114255550010683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127775005041 + 57127775005042.
It is an arithmetic number, because the mean of its divisors is an integer number (57127775005042).
Almost surely, 2114255550010083 is an apocalyptic number.
114255550010083 is a deficient number, since it is larger than the sum of its proper divisors (1).
114255550010083 is an equidigital number, since it uses as much as digits as its factorization.
114255550010083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120000, while the sum is 40.
The spelling of 114255550010083 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred fifty million, ten thousand, eighty-three".
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