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114255550009963 is a prime number
BaseRepresentation
bin11001111110101000110001…
…011110001101001001101011
3112222112201112201200001120001
4121332220301132031021223
5104433430331300304323
61043000135225243431
733031456020002545
oct3176506136151153
9488481481601501
10114255550009963
11334505633876aa
12109935a8633577
134b9a337c2c52b
14202ddd8c06695
15d320b08843ad
hex67ea3178d26b

114255550009963 has 2 divisors, whose sum is σ = 114255550009964. Its totient is φ = 114255550009962.

The previous prime is 114255550009919. The next prime is 114255550010083. The reversal of 114255550009963 is 369900055552411.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114255550009963 - 221 = 114255547912811 is a prime.

It is a super-2 number, since 2×1142555500099632 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114255550009903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127775004981 + 57127775004982.

It is an arithmetic number, because the mean of its divisors is an integer number (57127775004982).

Almost surely, 2114255550009963 is an apocalyptic number.

114255550009963 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255550009963 is an equidigital number, since it uses as much as digits as its factorization.

114255550009963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290000, while the sum is 55.

The spelling of 114255550009963 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred fifty million, nine thousand, nine hundred sixty-three".